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Q. The molecular mass of $ KMn{{O}_{4}} $ is M. The equivalent weight of $ KMn{{O}_{4}} $ , when it is converted into $ KMn{{O}_{4}} $ is:

JIPMERJIPMER 2002The d-and f-Block Elements

Solution:

In this conversion, the oxidation-state change of Mn is equal to 1. $ \overset{+\,7}{\mathop{KM{{O}_{4}}}}\,\xrightarrow{{}}\overset{+\,6}{\mathop{{{K}_{2}}Mn{{O}_{4}}}}\, $ Hence, equivalent weight of $ KMn{{O}_{4}}=\frac{\text{molecular}\,\text{mass}}{\text{change}\,\text{in}\,\text{oxidation}\,\text{state}} $ $ =\frac{M}{1}=M $