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Q.
The mole fraction of solute in an aqueous solvent is $0.1$. The molality of the solution is______ $m$.
Some Basic Concepts of Chemistry
Solution:
$x_{\text {solvent }}=1-x_{\text {solute }}$
$=1-0.1=0.9$
Assuming, moles of water $=0.9$ and moles of solute $=0.1$
Mass of water $=0.9 \times 18=16.20\, g =0.0162\, kg$
Molality $=\frac{\text { mol solute }}{\text { Mass of solvent }( kg )}$
$=\frac{0.1}{0.0162}=6.17\, m$