1. Tardigrade
  2. Question
  3. Chemistry
  4. The mole fraction of nitrogen, in a mixture containing 70 grams nitrogen, 120 grams of oxygen and 44 grams of carbon dioxide is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The mole fraction of nitrogen, in a mixture containing 70 grams nitrogen, 120 grams of oxygen and 44 grams of carbon dioxide is

Solutions

Solution:

Weight of nitrogen $=70\, g$;

Weight of oxygen $=120\, g$

and weight of carbon dioxide $=44 \,g$.

Moles of $N _{2}\left(n_{1}\right)=\frac{\text { Weight }}{\text { Molecular weight }}$

$=\frac{70}{28}=2.5$

Similarly, moles of $O _{2}\left(n_{2}\right)=\frac{120}{32}=3.75$

and moles of $CO _{2}\left(n_{3}\right)=\frac{44}{44}=1$

Therefore mole fraction of nitrogen $\left( N _{2}\right)$

$=\frac{n_{1}}{n_{1}+n_{2}+n_{3}}$

$=\frac{2.5}{2.5+3.75+1}$

$=\frac{2.5}{7.25}=0.34$