Question

The mole fraction of glucose $\left( C _{6} H _{12} O _{6}\right)$ in an aqueous binary solution is $0.1 .$ The mass percentage of water in it, to the nearest integer, is_________.

Answer 1

$X _{ C _{6} H _{12} O _{6}}=0.1$

Let total mole is $1$ mol then mole of glucose will be $0.1$ and mole of water will be $0.9$

so mass $\%$ of water $=\frac{0.9 \times 18}{0.1 \times 180+0.9 \times 18} \times 100$

$ = 47.36$