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Q. The mole fraction of ethanol in water is $0.08$. Its molality is

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Solution:

Molality $=\frac{X_{ EtOH }}{X_{ H _{2} O }} \times \frac{1000}{M W_{\text {solvent }}}$
$=\frac{0.08}{0.92} \times \frac{1000}{18}$
$=4.83 \,mol\, kg ^{-1}$