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Q. The mole fraction of dioxygen in a neon-dioxygen mixture is $0.18$. If the total pressure of the mixture is $25$ bar, the partial pressure of neon in the mixture would be

COMEDKCOMEDK 2014States of Matter

Solution:

Given $P_{total}$ = 25 bar,
$ x_{O_2} = 0.18 $
$\therefore \:\:\: x_{Ne} = 1 - 0.18 = 0.82$
$ p_{Ne} = x_{Ne} \times P_{total} = 0.82 \times 25 = 20.5 bar$