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  4. The mole fraction of benzene in a solution containing 39% by mass in an organic solvent of molecular mass 122 is

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Q. The mole fraction of benzene in a solution containing 39% by mass in an organic solvent of molecular mass 122 is

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Solution:

Mass of benzene $\left(w_2\right)=39\, g$
Mass of solvent $(w 1)=61\, g$
Molecular mass of benzene $\left(M_2\right)=78 \,g \,mol ^{-1}$
Molecular mass of solvent $\left(M_1\right)=122 \,g \,mol ^{-1}$
Mole fraction of benzene, $x_2$
$=\frac{w_2 / M_2}{w_1 / M_1+w_2 / M_2}$
$=\frac{39 / 78}{61 / 122+39 / 78}=\frac{0.5}{0.5+0.5}=0.5$