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Q.
The mole fraction of a solute in its one molal aqueous solution is:
NTA AbhyasNTA Abhyas 2022
Solution:
$w=1000 \, g \, \left(H_{2} O\right); \, n$ (solute) $=1 \, mol$
(as $1$ molal aqueous solution implies $1$ mol of solute in $1 \,kg$ of water)
$N $ (water) $ =\frac{W}{M}=\frac{1000}{18}=55.55$
Whereas
$n =$ number of moles of solute
$N =$ number of moles of water $\left(\left(\text{H}\right)_{\text{2}} \text{O}\right)$
$X_{\text{solute}}=\frac{n}{n + N}=\frac{1}{1 + 55.55}$
$=0.018$