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Q. The molarity of a solution obtained by mixing 800 m? of 0.5 M HCl with 200 mL of 1 M HCl will be

Jharkhand CECEJharkhand CECE 2012

Solution:

$ {{\underset{\text{Initial}}{\mathop{{{M}_{1}}{{V}_{1}}+{{M}_{2}}V}}\,}_{2}}=\underset{\text{Final}}{\mathop{{{M}_{3}}{{V}_{3}}}}\, $
$ {{V}_{3}}={{V}_{1}}+{{V}_{2}}=800+200=1000\,mL $
$ =0.5\times 800+1\times 200 $
$ ={{M}_{3}}\times 1000 $
$ {{M}_{3}}=\frac{600}{1000}=0.6\,M $