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Q. The molarity of a solution containing $5.0\, g$ of $ NaOH $ in $250\, mL$ solution is

Uttarkhand PMTUttarkhand PMT 2009

Solution:

Molanty $=\frac{\text { number of moles of solute }}{\text { volume of solution }}$
$=\frac{5 \times 1000}{40 \times 250}$
$\left[\because\right.$ moles of $\left.N a O H=\frac{5}{40}\right]=0.5\, M$