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  4. The molarity of 720 g of pure water is

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Q. The molarity of 720 g of pure water is

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Solution:

Molarity = $\frac{w_B (g) \times 1000}{M_B \times V_A (mL)}$
= $\frac{720 \times 1000}{18 \times 720} = 55.5 \,M$
[720 g of water = 720 mL of water] .