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Q. The molar internal energy of a gas at temperature T is $ {{U}_{m}} $ [T]. The molar internal energy at T = 0 is $ {{U}_{m}} $ (0). The correct expression that relates these two with appropriate contributions is

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Solution:

$ \Delta {{U}_{m}}={{C}_{V}}\Delta T $ $ {{\Delta }_{m}}(T)-{{U}_{m}}(0)={{C}_{V}}(T-0) $ $ {{U}_{m}}(T)-{{U}_{m}}(0)=\frac{5}{2}RT $ [ $ Cv=\frac{5}{2}R, $ for linear molecule, by taking translational and rotational] $ {{U}_{m}}(T)={{U}_{m}}(0)+\frac{5}{2}RT $