Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The molar conductivity of acetic acid at infinite dilution is $390.7$ and for $0.01\, M$ acetic acid is $3.907\, S\, cm^{2} mol^{-1}$. What is the $pH$ of solution?

Electrochemistry

Solution:

$\alpha=\frac{\wedge_{m}^{c}}{\wedge_{m}^{o}}=\frac{3.907}{390.7}=0.01$
image
$\therefore \left[H^{\oplus}\right]=c \alpha=0.01 \times 0.01=10^{-4} M$
$P H=-\log \left(10^{-4}\right)=4$