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Q. The molar conductivity of a conductivity cell filled with $10$ moles of $20\, mL\, NaCl$ solution is $\Lambda_{ m 1}$ and that of $20$ moles another identical cell heaving $80 \, mL \, NaCl$ solution is $\Lambda_{ m 2}$, The conductivities exhibited by these two cells are same. The relationship between $\Lambda_{ m 2}$ and $\Lambda_{ m 1}$ is

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Solution:

$ \Lambda_{ m }=\kappa \times \frac{1000}{ M } $
$ \Rightarrow \Lambda_{ m } \propto \frac{1}{ M }$
$ \frac{\Lambda_{ m _1}}{\Lambda_{ m _2}}=\frac{ M _2}{ M _1}=\frac{\frac{20}{80}}{\frac{10}{20}}=\frac{1}{4} \times \frac{2}{1}=\frac{1}{2} $
$\Rightarrow \Lambda_{ m _2}=2 \Lambda_{ m _1}$