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  4. The molar conductivities at infinite dilution of barium chloride, sulphuric arid and hydrochloric acid are 280,860 and 426 Scm 2 mol -1 respectively. The molar conductivity at infinite dilution of barium sulphate is S cm 2 mol -1 (Round off to the Nearest Integer).

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Q. The molar conductivities at infinite dilution of barium chloride, sulphuric arid and hydrochloric acid are 280,860 and $426\,Scm ^{2} mol ^{-1}$ respectively. The molar conductivity at infinite dilution of barium sulphate is _________ $S\,cm ^{2} mol ^{-1}$
(Round off to the Nearest Integer).

JEE MainJEE Main 2021Electrochemistry

Solution:

From Kohlrausch' s law

$\Lambda_{ m }^{\infty}\left( BaSO _{4}\right)=\lambda_{ m }^{\infty}\left( Ba ^{2+}\right)+\lambda_{ m }^{\infty}\left( SO _{4}^{2-}\right) $

$\Lambda_{ m }^{\infty}\left( BaSO _{4}\right)=\Lambda_{ m }^{\infty}\left( BaCl _{2}\right)+\Lambda_{ m }^{\infty}\left( H _{2} SO _{4}\right) $

$-2 \Lambda_{ m }^{\infty}( HCl ) $

$=280+860-2(426) $

$=288\,Scm ^{2} mol ^{-1}$