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Q. The molar conductance of $0.001 \, M$ acetic acid is $50 \,ohm ^{-1} \,cm ^{2} \,mol ^{-1}$. The maximum value of molar conductance of acetic acid is $250\,ohm ^{-1} \,cm ^{2} \,mol ^{-1} .$ What is the degree of dissociation $(\alpha)$ of acetic acid?

Electrochemistry

Solution:

Degree of dissociation $=\alpha=\frac{\Lambda_{c}}{\Lambda_{\infty}}=\frac{50}{250}=0.2$