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Q. The molality of a $H _{2} SO _{4}$ solution is $9 .$ The weight of the solute in $1 \,kg\, H _{2} SO _{4}$ solution is:

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Solution:

$9$ molal $H _{2} SO _{4}=9 \times 98\, g\, H _{2} SO _{4}$ in $1000 \,g\, H _{2} O$

$=882\, g\, H _{2} SO _{4}$ in $1882\, g\, H _{2} SO _{4}$ solution

$=\frac{882}{1882} \times 1000 \,g\, H _{2} SO _{4}$ in $1 \,kg$ solution

$=469\, g$