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Q.
The molality of $ 90\%H_{2}SO_{4} $ solution is [density $ =1.8\,g\,ml $ ]:
Punjab PMETPunjab PMET 2004Solutions
Solution:
The density of solution $=1.8\, g\, ml$
Weight of one litre of solution $=1800\, g$
$\therefore $ weight of $H _{2} SO _{4}$ in the solution
$=\frac{1800 \times 90}{100}$
$=1620\, g$
$\therefore $ weight of solvent $=1800-1620$
$=180\, gm$
$\therefore $ molality $=\frac{1620}{98} \times \frac{100}{180}$
$=91.8$