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Q. The molality of 15% by wt solution of $H_{2}SO_{4}$ is

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

15% $w/w$ solution weight of solute = 15 g

Weight of solvent = 85 g

$m=\frac{w_{A} \times 1000}{M_{A} \times w_{B}}$

$=\frac{15 \times 1000}{98 \times 85}=1.8$

$\left[A \rightarrow S o l u t e , B \rightarrow S o l v e n t \right]$