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Q. The molal lowering of vapour pressure for water at $100^{o}C$ , is

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Solution:

$\frac{P^{0} - P_{S}}{P^{0}}=\frac{n_{2}}{n_{1} + n_{2}}$

$P^{0}-P_{S}=\left[\frac{1}{1 + \frac{1000}{18}}\right]\times 760=13.43mm$