1. Tardigrade
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  3. Chemistry
  4. The molal elevation constant of water =0.52 K m -1. The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl ) should be

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Q. The molal elevation constant of water $=0.52\, K m ^{-1}$. The boiling point of $1.0$ molal aqueous $KCl$ solution (assuming complete dissociation of $KCl$ ) should be

Solutions

Solution:

$\Delta T_{ b }=K_{ b } \times m=0.52 \times 1 \times 2=1.04$
$\therefore T_{ b }=100+1.04=101.04^{\circ} C$