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Chemistry
The mojor product of the following reaction is: CH3C = CH xrightarrow[(ii) DI] (i) Dcl (1 equiv.)
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Q. The mojor product of the following reaction is : $CH_3C = CH \xrightarrow[(ii) DI] {(i) Dcl (1 equiv.)}$
JEE Main
JEE Main 2019
Hydrocarbons
A
$CH_3CD(Cl)CHD(I)$
67%
B
$CH_3CD_2CH(Cl)(I)$
0%
C
$CH_3CD(I)CHD(Cl)$
33%
D
$CH_3C(I)(Cl)CHD_2$
0%
Solution:
Correct answer is (d) $CH_3C(I)(Cl)CHD_2$
