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Q. The minimum wavelength for Balmer series is ______

Gujarat CETGujarat CET 2020

Solution:

$\frac{1}{\gamma}=R\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right)=R\left(\frac{1}{2^{2}}-\frac{1}{\infty^{2}}\right)$