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Q. The minimum value of $y=x(\ell \ln x)^2$ is-

Application of Derivatives

Solution:

$y=x(\ell n x)^2$
$y^{\prime}=x \cdot 2 \ell n x \cdot \frac{1}{x}+(\ell n x)^2$
image
$y$ is $\min$ at $x=1$
$\therefore y _{\min }=0$