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Q. The metal hydroxide which is soluble in excess of ammonium hydroxide is

COMEDKCOMEDK 2009The d-and f-Block Elements

Solution:

The metal hydroxide which is soluble in excess of ammonium hydroxide is $Cu ( OH )_{2}$. It forms soluble complex tetramminecupric hydroxide $\left[ Cu \left( NH _{3}\right)_{4}\right]( OH )_{2}$
$ Cu ( OH )_{2}+4 NH _{4} OH \rightarrow\left[ Cu \left( NH _{3}\right)_{4}\right]( OH )_{2}+4 H _{2} O $