The metal hydroxide which is soluble in excess of ammonium hydroxide is $Cu ( OH )_{2}$. It forms soluble complex tetramminecupric hydroxide $\left[ Cu \left( NH _{3}\right)_{4}\right]( OH )_{2}$
$
Cu ( OH )_{2}+4 NH _{4} OH \rightarrow\left[ Cu \left( NH _{3}\right)_{4}\right]( OH )_{2}+4 H _{2} O
$