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Q. The mechanism of the reaction : $A + 2B + C \to D$ is
(step 1) (fast) equilibrium $A + B \rightleftharpoons X$
(step 2) (slow) $X + C\to Y$
(step 3) (fast) $Y+B\to D$
Which rate law is correct?

Chemical Kinetics

Solution:

$r=K\left[X\right]\left[C\right]$
$K'=\frac{\left[X\right]}{\left[A\right]\left[B\right]}$
$r=K' \left[A\right]\left[B\right]\left[C\right]$