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Q. The mean of $ 100 $ items was $ 60 $ . Later it was found that two items were misread as $ 69 $ and $ 96 $ instead of $ 66 $ and $ 99 $ respectively. The correct mean of the $ 100 $ items is

J & K CETJ & K CET 2016Statistics

Solution:

Incorrect mean $= 60$,
Incorrect sum $= 6000$
$\therefore $ Correct sum $= 6000 -69 - 96 + 66 + 99$
$ = 6000$
$\therefore $ Correct mean $= \frac{6000}{100} =60$