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  4. The mean kinetic energy of one mole of gas per degree of freedom (on the basis of kinetic theory of gases) is

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Q. The mean kinetic energy of one mole of gas per degree of freedom (on the basis of kinetic theory of gases) is

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Solution:

The mean kinetic energy of one mole of gas $n$ degree of freedom.
$E=\frac{n}{2}RT$
The mean kinetic energy of one mole of gas per degree of freedom.
$E^{′}=\frac{E}{n}=\frac{\frac{n}{2} R T}{n}$
$E^{′}=\frac{1}{2}RT$