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  4. The mean deviation of the data 3,10,10,4,7,10,5 from the mean is

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Q. The mean deviation of the data $3,10,10,4,7,10,5$ from the mean is

Statistics

Solution:

We have, $3,10,10,4,7,10,5$
Mean $(\bar{x}) =\frac{3+10+10+4+7+10+5}{7} $
$ =\frac{49}{7}=7$
Mean deviation $=\frac{1}{n} \displaystyle\sum_{i=1}^7\left|x_i-\bar{x}\right|$
$= \frac{ \left[|3-7|+|10-7|+|10-7|+|4-7|+|7-7| +|10-7|+|5-7| \right]}{7} $
$= \frac{4+3+3+3+0+3+2}{7}=\frac{18}{7}=2.57$