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  4. The mean deviation of the data 2, 9, 9, 3, 6, 9, 4 from the mean is

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Q. The mean deviation of the data $2$, $9$, $9$, $3$, $6$, $9$, $4$ from the mean is

Statistics

Solution:

Mean $\bar{x} = \frac{2+9+9+3+6+9+4}{7}$
$= \frac{42}{7}=6$
$M.D. \left(\bar{x}\right) = \frac{\Sigma\left|x_{i} - \bar{x}\right|}{n}$
$= \frac{4+3+3+3+0+3+2}{7} = 2.57$