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Q. The mean deviation about the mean for the values $18, 20, 12, 14, 19, 22, 26, 16, 19, 24$ is

J & K CETJ & K CET 2010Statistics

Solution:

Here, $ =(n=10)= $ total number of observations. Mean deviation $ =\frac{\Sigma \,|{{x}_{i}}-\bar{x}|}{n}=\left( \frac{33}{10} \right)=3.3 $