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Q. The mean and the SD of $1,2,3,4,5,6 $ are

Statistics

Solution:

Mean $\bar{x}=\frac{1+2+3+4+5+6}{6}=\frac{21}{6}=\frac{7}{2}$
$ SD =\sigma =\sqrt{\frac{1}{n} \sum_{i}^{2}-(\bar{x})^{2}} $
$=\sqrt{\frac{1}{6}(1+4+9+16+25+36)-\frac{49}{4}} $
$=\sqrt{\frac{91}{6}-\frac{49}{4}}=\sqrt{\frac{182-147}{12}}$
$=\sqrt{\frac{35}{12}} $