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Q.
The maximum time period of any simple pendulum on the earth is
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Solution:
For maximum time period $ l\approx {{R}_{e}}=6400\,km $ As $ T=2\pi \sqrt{\frac{l}{g}}=2\times \pi \sqrt{\frac{600\times {{10}^{3}}}{9.8}} $ or $ T=84.5\,\min $