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Q.
The maximum possible number of points of intersection of 7 straight lines and 5 circles is:
Permutations and Combinations
Solution:
Solution: Maximum possible number of points of intersection of 7 lines is ${ }^7 C_2=21$.
Maximum possible number of points of intersection of 5 circles in $2\left({ }^5 C_2\right)=20$
[ $\because$ two circles can intersect in two distinct points.]
Maximum possible number of points of intersection of 5 circles and 7 lines is $2(5)(7)=70$
Thus, maximum possible number of points of intersection is
$21+20+70=111 $