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Q.
The maximum number of structural isomers (acyclic and cyclic) possible for $C _{4} H _{6}$ are
Organic Chemistry – Some Basic Principles and Techniques
Solution:
Consider the possible structures of the molecule. Either it will have a triple bond $CH _{3}- CH _{2}- C \equiv CH$ or two double bonds $CH _{2}= CH - CH = CH _{2}$ or one double bond in a ring
The isomer with a triple bond is $CH _{3}- C \equiv C - CH _{3}$.
The isomer with a double bond is $CH _{3}- CH = C = CH _{2}$.
The ring isomers are
Therefore, total isomers are seven.