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Q. The maximum number of possible optical isomers in $1$-bromo-$2$-methyl cyclobutane is

KCETKCET 2011Haloalkanes and Haloarenes

Solution:

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1 -bromo-2-methyl cyclobutane

represents asymmetric carbon atom.

No. of asymmetric carbon atom $=(n)=2$

$\therefore $ Total number of optical isomers $=2^{n}$

$=2^{2}=4$