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Q. The maximum number of possible interference maxima obtained on screen for slit seperation equal to twice the wavelength in Young's double slit experiment is :-

Wave Optics

Solution:

For interference maxima
$d \sin \theta= n \lambda$
when $n -2, \sin 0-1 \Rightarrow $ maxima at $\infty($ not possible)
$\therefore $ only 3 maxima possible