1. Tardigrade
  2. Question
  3. Chemistry
  4. The maximum number of molecules is present in

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The maximum number of molecules is present in

UP CPMTUP CPMT 2013Some Basic Concepts of Chemistry

Solution:

At $STP$,
$22.4\, L$ of $H_2 = 6.023 \times 10^{23}$ molecules
$15\,L$ of $H_2$ $=\frac{6.023 \times 10^{23} \times15}{22.4}$
$=4.033 \times 10^{23}$ molecules
$5\,L$ of $N_{2}=\frac{6.023 \times10^{23} \times5}{22.4}$
$=1.344\times10^{23}$ molecules
$2\,g$ of $H_{2}=6.023 \times10^{23}$ molecules
$0.5\,g$ of $H_{2}=\frac{6.023 \times10^{23}\times0.5}{2}$
$=1.505\times10^{23}$ molecules
$32\,g$ of $O_{2}=6.023 \times 10^{23}$ molecules
$10\,g$ of $O_{2}=\frac{6.023 \times 10^{23} \times10}{32}$
$=1.882 \times 10^{23}$ molecules