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Q.
The maximum number of electrons that can have principle quantum number, $n=3$ and spin quantum number, $m_s=-\frac{1}{2}$, is
Structure of Atom
Solution:
When $n=3, l=0,1,2$ i.e., there are $3 s, 3 p$ and $3 d$-orbital's. If all these orbitals are completely occupied as
Total 18 electrons, 9 electrons with $s=+\frac{1}{2}$ and 9 with
$s=-\frac{1}{2}$
