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  4. The maximum number of electrons that can have principal quantum number, n=3, and spin quantum number, m s =-1 / 2, is

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Q. The maximum number of electrons that can have principal quantum number, $n=3$, and spin quantum number, $m_{ s }=-1 / 2$, is

JEE AdvancedJEE Advanced 2011

Solution:

For principal quantum number $( n =3)$
Number of orbitals $= n ^{2}=9$
So, number of electrons with $m _{ s }=-\frac{1}{2}$ will be 9