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Q. The maximum number of electrons that can be accommodated in a orbit of hydrogen atom whose diameter is $16.92\, \mathring{A}$ is________.

Structure of Atom

Solution:

Diameter of hydrogen atom $=16.92\, \mathring{A}$

Radius of atom $=\frac{16.92}{2}=8.46 \,\mathring{A}$

Also, $r_{n}=\frac{0.53 n^{2}}{z} \,\mathring{A}$

$8.46=\frac{0.53 n ^{2}}{1}$

Or $n =4$

Therefore, the maximum number of electrons in the fourth orbit are

$=2 n^{2}=2 \times(4)^{2}=32$