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  4. The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volt is

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Q. The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volt is

IIT JEEIIT JEE 1997

Solution:

Given, the maximum kinetic energy: $K _{\max }=4 eV$
If $V _{0}$ be the stopping potential, then $K _{\max }= eV _{0}$
$
\Rightarrow eV _{0}=4 eV
$
$
\Rightarrow V _{0}=4 V
$