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  4. The maximum kinetic energy of a photoelectron is 3 eV . Its stopping potential is

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Q. The maximum kinetic energy of a photoelectron is $3 \, eV$ . Its stopping potential is

NTA AbhyasNTA Abhyas 2020

Solution:

Here,
$K_{max}=3 \, \text{eV}$
Maximum kinetic energy is given by:
$K_{max}=eV_{0} \\ 3 \, eV=e\times V_{0} \\ 3 \, V=V_{0}$
$\therefore $ Stopping potential $V_{0}=3 \, V$