1. Tardigrade
  2. Question
  3. Physics
  4. The maximum displacement of the particle executing SHM is 1 cm and the maximum acceleration is (1.57)2cm text/s2. Its time period is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The maximum displacement of the particle executing SHM is 1 cm and the maximum acceleration is $ {{(1.57)}^{2}}cm\text{/}{{s}^{2}}. $ Its time period is

CMC MedicalCMC Medical 2008

Solution:

Maximum acceleration $ =A{{\omega }^{2}} $ $ \Rightarrow $ $ {{\left( \frac{\pi }{2} \right)}^{2}}=1{{\left( \frac{2\pi }{T} \right)}^{2}} $ $ \left( \because \,1.57=\frac{\pi }{2} \right) $ $ \Rightarrow $ $ \frac{{{\pi }^{2}}}{4}=\frac{4{{\pi }^{2}}}{{{T}^{2}}} $ $ \Rightarrow $ $ {{T}^{2}}=\frac{4\times 4{{\pi }^{2}}}{{{\pi }^{2}}} $ $ \Rightarrow $ $ {{T}^{2}}=16 $ $ \Rightarrow $ $ T=4s $