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Q. The mass of proton is $1.0073\, u$ and that of neutron is $1.0087\, u ( u =$ atomic mass unit). The binding energy of ${ }_{2}^{4} He$ is (Given : helium nucleus mass $\approx 4.0015\, u$ )

AIPMTAIPMT 2003

Solution:

$BE =\Delta m \times 931$
$=[2(1.0087+1.0073)-4.0015] \times 931$
$=28.\,4\, Me V$