1. Tardigrade
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  3. Chemistry
  4. The mass of helium atom of mass number 4 is 4.0026 amu, while that of the neutron and proton are 1.0087 and 1.0078 respectively on the same scale. Hence, the nuclear binding energy per nucleon in the helium atom is nearly

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Q. The mass of helium atom of mass number $4$ is $4.0026$ amu, while that of the neutron and proton are $1.0087$ and $1.0078$ respectively on the same scale. Hence, the nuclear binding energy per nucleon in the helium atom is nearly

ManipalManipal 2008

Solution:

He atom has $ 2p+2n $
Hence,
$ \Delta m=(2\times 1.0078+2\times 1.0087)-4.0026 $
$ =0.0304\,amu $
$ \therefore $ energy released
$ =0.0304\times 931.5\,MeV $
$ =28.3\,MeV $
Binding energy per nucleon
$ =\frac{28.3}{4}=7\,MeV $ (approximately)