Q.
The mass of $CO _{2}$ that shall be obtained by heating $10\, kg$ of $80 \%$ pure limestone $\left( CaCO _{3}\right)$ is:
$CaCO _{3}( s ) \rightarrow CO _{2}( g )+ CaO ( s )$
Some Basic Concepts of Chemistry
Solution:
1 mol
1 mol
$100 \,g$
$44\, g$
$10\, kg$
$4.4 \,kg$
$\frac{80}{100} \times 10 kg$
$4.4 \times \frac{80}{100}$
$= 8 \,kg$
$=3.52\, kg$
| 1 mol | 1 mol |
|---|---|
| $100 \,g$ | $44\, g$ |
| $10\, kg$ | $4.4 \,kg$ |
| $\frac{80}{100} \times 10 kg$ | $4.4 \times \frac{80}{100}$ |
| $= 8 \,kg$ | $=3.52\, kg$ |