1. Tardigrade
  2. Question
  3. Physics
  4. The mass of a body m moving with a velocity v is given by m=(m0/√1-(v2)c2) where m0= rest mass, c= speed of light =3 × 108 ms -1. The approximate value of m (in .kg ) for m0=10 kg , v=3 × 107 ms -1 is .

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The mass of a body $m$ moving with a velocity $v$ is given by $m=\frac{m_{0}}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$ where $m_{0}=$ rest mass, $c=$ speed of light $=3 \times 10^{8} ms ^{-1}$. The approximate value of $m$ (in $\left.kg \right)$ for $m_{0}=10 kg , v=3 \times 10^{7} ms ^{-1}$ is ____.

Physical World, Units and Measurements

Solution:

$m=\frac{10}{\sqrt{1-\frac{9 \times 10^{14}}{9 \times 10^{16}}}}=\frac{10}{\sqrt{1-\frac{1}{100}}}=\frac{10}{1}=10$