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  4. The mass of a 73Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of 73Li nucleus is nearly

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Q. The mass of a $^7_3$Li nucleus is $0.042\, u$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of $^7_3$Li nucleus is nearly

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Solution:

For $^7_3$Li nucleus ,
Mass defect, $\Delta M=0.042 u$
$ \because \, 1 u=931.5 MeV/c^2$
$\therefore \, \, \Delta M=0.042 \times 931.5 MeV/c^2$
$ =39.1 \,MeV/c^2$
Binding energy, $E_b =\Delta Mc^2$
$ =\bigg(39.1 \frac{MeV}{c^2}\bigg)c^2$
$ =39.1 \,MeV$
Binding energy per nucleon,
$E_{bn}=\frac{E_b}{A}=\frac{39.1 \,MeV}{7}$
$=5.6 \,MeV$