Question

The mass of $_{7} N^{15}$ is $15.00011$ amu, mass of ${ }_{8} O^{16}$ is $15.99492$ amu and $mP =1.00783$ amu. Determine binding energy of last proton of ${ }_{8} O^{16}$

• A. 2.13 MeV
• B. 0.13 MeV
• C. 10 MeV
• D. 12.13 MeV

Answer 1

Answer: (D)

$M\left({ }_{8} O^{16}\right)=M\left({ }_{7} N^{15}\right)+1 m_{p}$
binding energy of last proton
$=M\left(N^{15}\right)+m_{p}-M\left({ }_{1} O^{16}\right)$
$=15.00011+1.00783-15.99492$
$=0.01302 \,amu =12.13 \,MeV$